Documentation > CMS Template API Library > Util > DeserializeXml(String,Type)

DeserializeXml

Define a class that uses [XmlElement], [XmlAttribute], and other tags and you can then create an object from XML with this method.

public System.Object DeserializeXml(String,Type)


Returns

The un-serialized XML.

Parameters

NameDescriptionType
xml The XML file to deserialize of specified object type System.String
objType Object of specified type used to deserialize an instance of XML System.Type

Code Example

C#

Sample: 
//create the class you will use. (system/library/userlist.cs)
public class UserList
{
    [XmlElement]
    public List<string> Name { get; set; }
 
    public UserList()
    {
      Name = new List<string>();
    }
}

//-- serialize --
List<string> nameList = new List<string>();
nameList.Add("Bob");
nameList.Add("Ralph");
UserList userListClass = new UserList() { Name = nameList };
 
string xml = Util.SerializeXml(userListClass);
//xml output will render the following:
<?xml version="1.0"?>
<UserList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Name>Bob</Name>
  <Name>Ralph</Name>
</UserList>

//-- deserialize --
UserList deserializedUserListClass = (UserList)Util.DeserializeXml(xml, typeof(UserList));
Out.WriteLine("First User from Xml: " + deserializedUserListClass.Name[0]);
Out.WriteLine("Second User from Xml: " + deserializedUserListClass.Name[1]);

//output will render the following:
First User from Xml: Bob
Second User from Xml: Ralph

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